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Laws of Motion question

2015 · Q131
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Laws of Motion question

2015 · Q131

NEETPhysicsLaws of MotionMCQ+4 / −1
Two stones of masses m and 2m are whirled in horizontal circles, the heavier one in a radius r2{r \over 2}2r​ and the lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they exprience same centripetal forces. The value of n is
  1. A
    4
  2. B
    1
  3. C
    2
  4. D
    3
View written solutionFree

Correct answer: C

According to question, two stones experience same centripetal force  i.e. FC1 = FC2

or mv12r=2mv22(r/2)⇒V12=4V22{{mv_1^2} \over r} = {{2mv_2^2} \over {\left( {r/2} \right)}} \Rightarrow V_1^2 = 4V_2^2rmv12​​=(r/2)2mv22​​⇒V12​=4V22​

So, V1 = 2V2 i.e., n = 2

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