NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
For the given cycle, the work done during isobaric process is:

- A200 J
- BZero
- C400 J
- D600 J
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Correct answer: D

$\mathrm{AB}$ is isobaric process
$$\begin{aligned} \& \mathrm{W}_{\mathrm{AB}}=\mathrm{P}\left(\mathrm{V}_2-\mathrm{V}_1\right) \\\\ \& \mathrm{W}_{\mathrm{AB}}=3 \times 10^2(3-1) \\\\ \& \mathrm{W}_{\mathrm{AB}}=3 \times 100 \times 2 \\\\ \& \mathrm{~W}_{\mathrm{AB}}=600 \mathrm{~J} \end{aligned}$$
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