NEETPhysicsGravitationMCQ+4 / −1
An object of mass falls from point to as shown in figure. The change in its weight, corrected to the nearest integer is ( is the radius of the earth)
- A49 N
- B89 N
- C5 N
- D10 N
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Correct answer: A
$$M g^{\prime}=M g \frac{R^2}{(R+h)^2}$$
At $A$ $$\quad M g^{\prime}=M g \frac{R^2}{(R+2 R)^2}=\frac{M g}{9}$$
At $$B \quad M g^{\prime}=M g \frac{R}{\left(R+\frac{3 R}{2}\right)^2}=\frac{M g \cdot 4}{25}$$
Change in weight $$=M g \frac{4}{25}-\frac{M g}{9}=49 \mathrm{~N}$$
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