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Gravitation question

2016 · Q150
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Gravitation question

2016 · Q150

NEETPhysicsGravitationMCQ+4 / −1
A satellite of mass m is orbiting the earth (of radius R) at a height h from its surface. The total energy of the satellite in terms of g0, the value of acceleration due to gravity at the earth's surface, is
  1. A
    mg0R22(R+h){{m{g_0}{R^2}} \over {2\left( {R + h} \right)}}2(R+h)mg0​R2​
  2. B
    −mg0R22(R+h)- {{m{g_0}{R^2}} \over {2\left( {R + h} \right)}}−2(R+h)mg0​R2​
  3. C
    2mg0R2R+h{{2m{g_0}{R^2}} \over {R + h}}R+h2mg0​R2​
  4. D
    −2mg0R2R+h- {{2m{g_0}{R^2}} \over {R + h}}−R+h2mg0​R2​
View written solutionFree

Correct answer: B

Total mechanical energy of satellite is given by

E = – GMm/2r

Here, r = R + h

And, GM = goR2

So, E = – mgoR2/2(R+h)

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