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Geometrical Optics question

2013 · Q121
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Geometrical Optics question

2013 · Q121

NEETPhysicsGeometrical OpticsMCQ+4 / −1
For a normal eye, the cornea of eye provides a converging power of 40 D and the least converging power of the eye lens behinf the cornea is 20 D. Using this information, the distance between the retina and the cornea-eye lens can be estimated to be
  1. A
    1.67 cm
  2. B
    1.5 cm
  3. C
    5 cm
  4. D
    2.5 cm
View written solutionFree

Correct answer: A

Pcornea = + 40 D

Pe = + 20 D

Total power of combination = 40 + 20 = 60 D

Focal length of combination = 160×100{1 \over {60}} \times 100601​×100 cm = 53{5 \over 3}35​ cm

For minimum converging state of eye lens,

u = -∞\infty ∞ v = ? f = 53{5 \over 3}35​

From lens formula,

1f=1v−1u{1 \over f} = {1 \over v} - {1 \over u}f1​=v1​−u1​

⇒\Rightarrow⇒ v = 53{5 \over 3}35​ cm

Distance between retina and cornea-eye lens

= 53{5 \over 3}35​ cm = 1.67 cm

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