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Geometrical Optics question

2010 · Q80
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Geometrical Optics question

2010 · Q80

NEETPhysicsGeometrical OpticsMCQ+4 / −1
A rays of light is incident on a 60o prism at the minimum deviation position. The angle of refraction at the first face (i.e., incident face) of the prism is
  1. A
    zero
  2. B
    30o
  3. C
    45o
  4. D
    60o
View written solutionFree

Correct answer: B

Angle of prism, A = r1 + r2

For minimum deviation r1 = r2 = r


∴\therefore∴ A = 2r

Given, A = 60°

Hence, r = A2{A \over 2}2A​ = 60∘2{{60^\circ } \over 2}260∘​ = 30o

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