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Geometrical Optics question

2003 · Q141
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Geometrical Optics question

2003 · Q141

NEETPhysicsGeometrical OpticsMCQ+4 / −1
A convex lens is dipped in a liquid whose refractive index is equal to the refractive index of the lens. Then its focal length will
  1. A
    become zero
  2. B
    become infinite
  3. C
    become small, but non-zero
  4. D
    remain unchanged
View written solutionFree

Correct answer: B

1f=(μ−1)(1R1−1R2){1 \over f} = \left( {\mu - 1} \right)\left( {{1 \over {{R_1}}} - {1 \over {{R_2}}}} \right)f1​=(μ−1)(R1​1​−R2​1​)

Where μ=μconvex lensμliquid\mu = {{{\mu _{convex\,lens}}} \over {{\mu _{liquid}}}}μ=μliquid​μconvexlens​​ = 1

∴\therefore∴ 1f=(1−1)(1R1−1R2)=0{1 \over f} = \left( {1 - 1} \right)\left( {{1 \over {{R_1}}} - {1 \over {{R_2}}}} \right) = 0f1​=(1−1)(R1​1​−R2​1​)=0

⇒\Rightarrow⇒ f = ∞\infty ∞

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