NEETPhysicsElectrostaticsMCQ+4 / −1
An electron falls from rest through a vertical
distance h in a uniform and vertically upward
directed electric field E. The direction of electric
field is now reversed, keeping its magnitude the
same. A proton is allowed to fall from rest in it
through the same vertical distance h. The time
of fall of the electron, in comparison to the time
of fall of the proton is
- Asmaller
- B5 times greater
- C10 times greater
- Dequal
View written solutionFree
Correct answer: A
Force experienced by a charged particle in
an electric field, F = qE
As F = ma
ma = qE
a =
As electron and proton both fall from same height at
rest. Then initial velocity = 0
From the formula, s = ut +
h =
h =
t =
t as ‘q’ is same for electron and
proton.
Since, electron has smaller mass so it will take
smaller time.
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