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Electromagnetic Induction question

2024 · Q178
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Electromagnetic Induction question

2024 · Q178

NEETPhysicsElectromagnetic InductionMCQ+4 / −1

Let us consider two solenoids AAA and BBB, made from same magnetic material of relative permeability μr\mu_rμr​ and equal area of cross-section. Length of AAA is twice that of BBB and the number of turns per unit length in AAA is half that of BBB. The ratio of self inductances of the two solenoids, LA:LBL_A: L_BLA​:LB​ is

  1. A
    1:21: 21:2
  2. B
    2:12: 12:1
  3. C
    8:18: 18:1
  4. D
    1:81: 81:8
View written solutionFree

Correct answer: A

$$\begin{aligned} & L=\mu_0 \mu_r \times n \times A \times N \\ & L=\mu_0 \mu_r n \times A \times \frac{N}{I} \times I \\ & L=\mu_0 \mu_r \times n^2 \times A \times I \Rightarrow L \propto n^2 I \\ & \Rightarrow \frac{L_A}{L_B}=\frac{n_A^2}{n_B^2} \times \frac{I_A}{I_B} \\ & \Rightarrow \frac{L_A}{L_B}=\frac{1}{4} \times 2=\frac{1}{2} \end{aligned}$$

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