For photoelectric emission from certain metal the cutoff frequency is \upsilon . If radiation of frequency 2 \upsilon impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)

Dual Nature of Radiation and Matter question

2013 · Q136

Dual Nature of Radiation and Matter question

2013 · Q136

View written solutionFree

Correct answer: A

Work function, $\phi$ = h $\nu$

According to Einstein’s photoelectric equation

${1 \over 2}mv_{\max }^2$ = h(2 $\nu$ ) - h $\nu$

$\Rightarrow$ ${1 \over 2}mv_{\max }^2 = h\nu$

$\Rightarrow$ $v_{\max }^2 = {{2h\nu } \over m}$

$\Rightarrow$ v_max = $\sqrt {{{2h\upsilon } \over m}}$

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Dual Nature of Radiation and Matter question

2013 · Q136

Dual Nature of Radiation and Matter question

2013 · Q136

View written solutionFree

Correct answer: A

Work function, $\phi$ = h $\nu$

According to Einstein’s photoelectric equation

${1 \over 2}mv_{\max }^2$ = h(2 $\nu$ ) - h $\nu$

$\Rightarrow$ ${1 \over 2}mv_{\max }^2 = h\nu$

$\Rightarrow$ $v_{\max }^2 = {{2h\nu } \over m}$

$\Rightarrow$ v_max = $\sqrt {{{2h\upsilon } \over m}}$