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Dual Nature of Radiation and Matter question

2010 · Q155
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Dual Nature of Radiation and Matter question

2010 · Q155

NEETPhysicsDual Nature of Radiation and MatterMCQ+4 / −1
A source S1 is producing, 1015 photons per second of wavelength 5000 A∘\mathop A\limits^ \circA∘​. Another source S2 is producing 1.02 ×\times× 1015 photons per second of wavelength 5100 A∘\mathop A\limits^ \circA∘​. Then, (power of S2)/(power of S1) is equal to
  1. A
    1.00
  2. B
    1.02
  3. C
    1.04
  4. D
    0.98
View written solutionFree

Correct answer: A

Power of S2
Power of S1
= $${{{n_2}\left[ {{{hc} \over {{\lambda _2}}}} \right]} \over {{n_1}\left[ {{{hc} \over {{\lambda _1}}}} \right]}}$$ = $${{{n_2}{\lambda _1}} \over {{n_1}{\lambda _2}}}$$

= $${{1.02 \times {{10}^{15}} \times 5000} \over {{{10}^{15}} \times 5100}}$$ = 1
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