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Current Electricity question

2015 · Q114
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Current Electricity question

2015 · Q114

NEETPhysicsCurrent ElectricityMCQ+4 / −1
A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm all connected in series. If the ammeter has a coil of resistance 480 ohm and a shunt of 20 ohm, the reading in the ammeter will be
  1. A
    2A
  2. B
    1A
  3. C
    0.5 A
  4. D
    0.25 A
View written solutionFree

Correct answer: C

From circuit diagram

AIPMT 2015 Physics - Current Electricity Question 103 English Explanation

Resistance of ammeter
= 480×20480+20=19.2Ω{{480 \times 20} \over {480 + 20}} = 19.2\Omega 480+20480×20​=19.2Ω

Total resistance R = 40.8 + 19.2 = 60Ω\OmegaΩ

Reading in the ammeter i=VRi = {V \over R}i=RV​

=3040.8+19.2=0.5A = {{30} \over {40.8 + 19.2}} = 0.5A=40.8+19.230​=0.5A

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