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Alternating Current question

2011 · Q90
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Alternating Current question

2011 · Q90

NEETPhysicsAlternating CurrentMCQ+4 / −1
A coil has resistance 30 ohm and inductive reactance 20 ohm at 50 Hz frequency. If an ac source, of 200 volt, 100 Hz, is connected across the coil, the current in the coil will be
  1. A
    2.0 A
  2. B
    4.0 A
  3. C
    8.0 A
  4. D
    2013A{{20} \over {\sqrt {13} }}A13​20​A
View written solutionFree

Correct answer: B

Current flowing in the coil is

I = 200Z=200R2+(ωL)2=200(30)2+(40)2{{200} \over Z} = {{200} \over {\sqrt {{R^2} + {{\left( {\omega L} \right)}^2}} }} = {{200} \over {\sqrt {{{\left( {30} \right)}^2} + {{\left( {40} \right)}^2}} }}Z200​=R2+(ωL)2​200​=(30)2+(40)2​200​ = 4 A

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