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Thermodynamics question

2023 · Q115
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Thermodynamics question

2023 · Q115

NEETChemistryThermodynamicsMCQ+4 / −1

The equilibrium concentrations of the species in the reaction A+B⇌C+D\mathrm{A}+\mathrm{B} \rightleftharpoons \mathrm{C}+\mathrm{D}A+B⇌C+D are 2,3,102,3,102,3,10 and 6 mol6 \mathrm{~mol}6 mol L−1\mathrm{L}^{-1}L−1, respectively at 300 K.ΔG0300 \mathrm{~K} . \Delta \mathrm{G}^{0}300 K.ΔG0 for the reaction is (R=2cal/mol K)(\mathrm{R}=2 \mathrm{cal} / \mathrm{mol} ~\mathrm{K})(R=2cal/mol K)

  1. A
    −137.26 cal-137.26 ~\mathrm{cal}−137.26 cal
  2. B
    −1381.80 cal-1381.80 ~\mathrm{cal}−1381.80 cal
  3. C
    −13.73 cal-13.73 ~\mathrm{cal}−13.73 cal
  4. D
    1372.60 cal1372.60 ~\mathrm{cal}1372.60 cal
View written solutionFree

Correct answer: B

$$\mathrm{A}+\mathrm{B} \rightleftharpoons \mathrm{C}+\mathrm{D}$$

$$ \begin{aligned} {[A] } & =2 \mathrm{~mol} \mathrm{~L}^{-1} \\ {[B] } & =3 \mathrm{~mol} \mathrm{~L}^{-1} \\ {[C] } & =10 \mathrm{~mol} \mathrm{~L}^{-1} \\ {[D] } & =6 \mathrm{~mol} \mathrm{~L}^{-1} \\ \Delta \mathrm{G}^{0} & =-2.303 \mathrm{RT} \log \mathrm{K}_{\mathrm{eq}} \\ & =-2.303 \mathrm{RT} \log \frac{[\mathrm{C}][\mathrm{D}]}{[\mathrm{A}][\mathrm{B}]} \\ & =-2.303 \times 2 \times 300 \times \log \frac{10 \times 6}{2 \times 3} \\ & =-2.303 \times 2 \times 300 \times \log 10 \\ & =-1381.8 \mathrm{~cal} \end{aligned} $$

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