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Thermodynamics question

2011 · Q77
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Thermodynamics question

2011 · Q77

NEETChemistryThermodynamicsMCQ+4 / −1
Consider the following processes :

H (kJ/mol)
1/2A →\to→ B +150
3B  →\to→ 2C + D -125
E + A  →\to→ 2D +350

For B + D →\to→ E + 2C, Δ\DeltaΔH will be
  1. A
    525 kJ/mol
  2. B
    −-−175 kJ/mol
  3. C
    −-− 325 kJ/mol
  4. D
    325 kJ/mol
View written solutionFree

Correct answer: B

H (kJ/mol)
1/2A $ \to $ B+150
3B  $ \to $ 2C + D-125
E + A  $ \to $ 2D+350
___________________________________
   B + D $ \to $ E + 2C;

$\Delta $H = (300 - 125 - 350) = - 175 kJ/mol
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