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Some Basic Concepts of Organic Chemistry question

2013 · Q118
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Some Basic Concepts of Organic Chemistry question

2013 · Q118

NEETChemistrySome Basic Concepts of Organic ChemistryMCQ+4 / −1
Homolytic fission of the following alkanes forms free radicals CH3 −-− CH3, CH3 −-− CH2 −-− CH3, (CH3)2CH −-− CH3, CH3 −-− CH2 −-−CH(CH3)2.
Increasing order of stability of the radicals is
  1. A
    &(CH3)2C∙ − CH2CH3 <CH3 − C∙H− CH3&<CH3 − C∙H2 <(CH3)3C∙\begin{aligned} \& {\left( {C{H_3}} \right)_2}\mathop C\limits^ \bullet \, - \,C{H_2}C{H_3}\, \lt C{H_3}\, - \,\mathop C\limits^ \bullet H - \,C{H_3} \\ \& \lt C{H_3}\, - \,\mathop C\limits^ \bullet {H_2}\, \lt {\left( {C{H_3}} \right)_3}\mathop C\limits^ \bullet \\\end{aligned}&(CH3​)2​C∙​−CH2​CH3​<CH3​−C∙​H−CH3​&<CH3​−C∙​H2​<(CH3​)3​C∙​​
  2. B
    &CH3 − C∙H2 < CH3 − C∙HH − CH3 <&(CH3)2C∙ − CH2 − CH3 < (CH3)3C∙\begin{aligned} \& C{H_3}\, - \,\mathop C\limits^ \bullet {H_2}\, \lt \,C{H_3}\, - \,\mathop C\limits^ \bullet HH\, - \,C{H_3}\, \lt \\ \& {\left( {C{H_3}} \right)_2}\mathop C\limits^ \bullet \, - \,C{H_2}\, - \,C{H_3}\, \lt \,{\left( {C{H_3}} \right)_3}\mathop C\limits^ \bullet \\\end{aligned}&CH3​−C∙​H2​<CH3​−C∙​HH−CH3​<&(CH3​)2​C∙​−CH2​−CH3​<(CH3​)3​C∙​​
  3. C
    &CH3−C∙H2<CH3−C∙H−CH3<&(CH3)3C∙ <(CH3)2C∙ −CH2CH3\begin{aligned} \& C{H_3} - \mathop C\limits^ \bullet {H_2} \lt C{H_3} - \mathop C\limits^ \bullet H - C{H_3} \lt \\ \& {\left( {C{H_3}} \right)_3}\mathop C\limits^ \bullet \, \lt {\left( {C{H_3}} \right)_2}\mathop C\limits^ \bullet \, - C{H_2}C{H_3} \\\end{aligned}&CH3​−C∙​H2​<CH3​−C∙​H−CH3​<&(CH3​)3​C∙​<(CH3​)2​C∙​−CH2​CH3​​
  4. D
    &(CH3)3C∙ <(CH3)2C∙ −CH2CH3<&CH3−C∙H−CH3<CH3−C∙H2\begin{aligned} \& {\left( {C{H_3}} \right)_3}\mathop C\limits^ \bullet \, \lt {\left( {C{H_3}} \right)_2}\mathop C\limits^ \bullet \, - C{H_2}C{H_3} \lt \\ \& C{H_3} - \mathop C\limits^ \bullet H - C{H_3} \lt C{H_3} - \mathop C\limits^ \bullet {H_2} \\\end{aligned}&(CH3​)3​C∙​<(CH3​)2​C∙​−CH2​CH3​<&CH3​−C∙​H−CH3​<CH3​−C∙​H2​​
View written solutionFree

Correct answer: B

Stability depends on number of hyperconjugative structure. More the number of hyperconjugative structure, the greater is the stability.

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