Given that

w_s = 6.5 g, w_A = 100 g

p_s = 732 mm of Hg

k_b = 0.52, T^o_b = 100^oC

p^o = 760 mm of Hg

${{{p^o} - {p_s}} \over {{p^o}}} = {{{n_2}} \over {{n_1}}}$

$\Rightarrow$ ${{760 - 732} \over {760}} = {{{n_2}} \over {{{100} \over {18}}}}$

$\Rightarrow$ n₂ = 0.2046 mol

$\Delta$T_b = K_b × m

T_b - T^o_b = ${k_b} \times {{{n_2} \times 1000} \over {{w_{A\left( g \right)}}}}$

$\Rightarrow$ T_b - 100^oC = ${{0.52 \times 0.2046 \times 1000} \over {100}}$ = 1.06

$\Rightarrow$ T_b = 101.06 ^oC