NEETChemistryP Block ElementsMCQ+4 / −1
The formation of the oxide ion, O2(g) from oxygen atom requires first an exthermic and then an endothermic step as shown below:
O(g) + e O(g); fHo = 141 kJ mol1
O(g) + e O2(g); fHo = +780 kJ mol1
Thus, process of formation of O2 is isoelectronic with neon. It is due to the fact that,
O(g) + e O(g); fHo = 141 kJ mol1
O(g) + e O2(g); fHo = +780 kJ mol1
Thus, process of formation of O2 is isoelectronic with neon. It is due to the fact that,
- AO ion has comparatively smaller size than oxygen atom
- Boxygen is more electronegative
- Caddition of electron in oxygen results in larger size of the ion
- Delectron repulsion outweighs the stability gained by achieving noble gas configuration.
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Correct answer: D
The process of formation of O2– in gas phase is unfavourable even though O2– is isoelectronic with neon because electron repulsion outweigh the stability gained by achieving noble gas configuration.
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