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Nuclear Chemistry question

2001 · Q103
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Nuclear Chemistry question

2001 · Q103

NEETChemistryNuclear ChemistryMCQ+4 / −1
A human body required 0.01 m activity of radioactive substance after 24 hours. Half life of radioactive substance is 6 hours. Then inhection of maximum activity of radioactive substance that can be injected is
  1. A
    0.08
  2. B
    0.04
  3. C
    0.16
  4. D
    0.32
View written solutionFree

Correct answer: C

At the end of 24 hrs. activity = 0.01 M

Half life = 6 hrs.

In 24 hrs. there are 24/6 = 4 half life.

Activity of substance after n half-life = A2n{A \over {{2^n}}}2nA​

∴\therefore∴ A24=0.01{A \over {{2^4}}} = 0.0124A​=0.01

⇒\Rightarrow⇒ A = 0.16

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