NEETChemistryHydrocarbonsMCQ+4 / −1
The compound
on reaction with NaIO4 in the presence of KMnO4 gives
on reaction with NaIO4 in the presence of KMnO4 gives
- ACH3COCH3
- BCH3COCH3 + CH3COOH
- CCH3COCH3 + CH3CHO
- DCH3CHO + CO2
View written solutionFree
Correct answer: B

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