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D and F Block Elements question

2024 · Q125
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D and F Block Elements question

2024 · Q125

NEETChemistryD and F Block ElementsMCQ+4 / −1

The E∘\mathrm{E}^{\circ}E∘ value for the Mn3+/Mn2+\mathrm{Mn}^{3+} / \mathrm{Mn}^{2+}Mn3+/Mn2+ couple is more positive than that of Cr3+/Cr2+\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}Cr3+/Cr2+ or Fe3+/Fe2+\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}Fe3+/Fe2+ due to change of

  1. A
    d5d^5d5 to d4d^4d4 configuration
  2. B
    d5d^5d5 to d2d^2d2 configuration
  3. C
    d4d^4d4 to d5d^5d5 configuration
  4. D
    d3d^3d3 to d5d^5d5 configuration
View written solutionFree

Correct answer: C

$$ \mathrm{E}_{\mathrm{Mn}^{3+} / \mathrm{Mn}^{2+}}^0>\mathrm{E}_{\mathrm{Cr}^{3+} / \mathrm{Cr}^{2+}}^{\circ} \text { or } \mathrm{E}_{\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}}^{\circ} $$

Electronic configuration of $$\mathrm{Mn}^{3+}=[\mathrm{Ar}] 3 d^4$$

Electronic configuration of $$\mathrm{Mn}^{2+}=[\mathrm{Ar}] 3 d^5$$

Electronic configuration of $$\mathrm{Cr}^{3+}=[\mathrm{Ar}] 3 d^3$$

Electronic configuration of $$\mathrm{Cr}^{2+}=[\mathrm{Ar}] 3 d^4$$

As $\mathrm{Mn}^{3+}$ from $d^4$ configuration goes to more stable $d^5$ configuration (Half filled), due to more exchange energy in $d^5$ configuration.

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