NEETChemistryCoordination CompoundsMCQ+4 / −1
Considering H2O as a weak field ligand, the number of unpaired electrons in [Mn(H2O)6]2+ will be (atomic number of Mn = 25)
- Athree
- Bfive
- Ctwo
- Dfour
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Correct answer: B
In [Mn(H2O)6]2+
Mn+2 = [Ar] 3d54s0

In presence of weak field ligand H2O, there will be no pairing of electrons. So it will form a high spin complex, i.e. the number of unpaired electrons = 5.
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