The Arrhenius equation is given as

$$\begin{aligned} \& \mathrm{k}=\mathrm{Ae}-\frac{\mathrm{E}_{\mathrm{a}}}{R T} \\ \& \therefore \quad \ln \mathrm{k}=\ln \mathrm{A}-\frac{\mathrm{E}_{\mathrm{a}}}{\mathrm{RT}} \end{aligned}$$

$$\ln \mathrm{k~} \text{v/s} ~\frac{1}{\mathrm{~T}} \text { gives a straight line graph with slope }=-\frac{E_a}{R} \text { and intercept }=\ln A$$