Match List - I with List - II.
| List - I | List - II | ||
|---|---|---|---|
| (A) | Monohybrid Cross | (I) | 1 : 1 |
| (B) | Dihybrid Cross | (II) | 1 : 2 : 1 |
| (C) | Incomplete dominance | (III) | 3 : 1 |
| (D) | Test Cross | (IV) | 9 : 3 : 3 : 1 |
Choose the correct answer from the options given below :
- A(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- B(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
- C(A)-(II), (B)-(III), (C)-(IV), (D)-(I)
- D(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
View written solutionFree
Correct answer: A
Option A : (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
Explanation :
(A) Monohybrid Cross : Monohybrid crosses are those that involve one pair of contrasting traits. In monohybrid crosses, the phenotypic ratio of the F2 generation is typically 3:1 (III).
(B) Dihybrid Cross : Dihybrid crosses are those that involve two pairs of contrasting traits. In dihybrid crosses, the phenotypic ratio of the F2 generation is typically 9:3:3:1 (IV).
(C) Incomplete Dominance : Incomplete dominance is when neither allele for a specific trait is dominant over the other. As a result, the phenotype of the heterozygote is somewhere in between the two homozygotes. The phenotypic ratio in such a case is typically 1:2:1 (II).
(D) Test Cross : A test cross involves crossing an individual exhibiting the dominant phenotype (but unknown genotype) with a homozygous recessive individual. The phenotypic ratio can be 1:1 (I) if the dominant individual was a heterozygote. If the dominant individual was a homozygote, all offspring will exhibit the dominant phenotype.
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