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Evolution question

2016 · Q73
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Evolution question

2016 · Q73

NEETBiologyEvolutionMCQ+4 / −1
In Hardy-Weinberg equation, the frequency of heterozygous individual is represented by
  1. A
    pq
  2. B
    p2
  3. C
    2pq
  4. D
    q2
View written solutionFree

Correct answer: C

In a stable population, for a gene with two alleles, ‘A’ (dominant) and ‘a’ (recessive), if the frequency of ‘A’ is p and the frequency of ‘a’ is q, then the frequencies of the three possible genotypes (AA, Aa and aa) can be expressed by the HardyWeinberg equation:
p2 + 2pq + q2 = 1
where p2 = Frequency of AA (homozygous dominant) individuals
q2 = Frequency of aa (homozygous recessive) individuals
2pq = Frequency of Aa (heterozygous) individuals

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