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Units and Measurements question

2008 · Shift 0 · Q87
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Units and Measurements question

2008 · Shift 0 · Q87

JEE MainPhysicsUnits and MeasurementsMCQ+4 / −1
A body of mass m = 3.513 kg is moving along the x-axis with a speed of 5.00 ms−1. The magnitude of its momentum is recorded as
  1. A
    17.6 kg ms-1
  2. B
    17.565 kg ms-1
  3. C
    17.56 kg ms-1
  4. D
    17.57 kg ms-1
View written solutionFree

Correct answer: A

  1. Given data

    • Mass: m=3.513 kgm = 3.513\,\text{kg}m=3.513kg
    • Speed: v=5.00 m s−1v = 5.00\,\text{m s}^{-1}v=5.00m s−1
  2. Formula for momentum

    The magnitude of momentum is p=mvp = mvp=mv

  3. Substitute the values

    p=3.513×5.00p = 3.513 \times 5.00p=3.513×5.00

    p=17.565 kg m s−1p = 17.565\,\text{kg m s}^{-1}p=17.565kg m s−1

  4. Apply significant figures

    • 3.5133.5133.513 has 4 significant figures
    • 5.005.005.00 has 3 significant figures

    In multiplication, the result should have the same number of significant figures as the factor with the least number of significant figures.

    So, the answer should be reported to 3 significant figures.

    17.565→17.617.565 \to 17.617.565→17.6

  5. Match with options

    • A: 17.6 kg m s−117.6\,\text{kg m s}^{-1}17.6kg m s−1 ✅
    • B: 17.565 kg m s−117.565\,\text{kg m s}^{-1}17.565kg m s−1 ❌ (too many significant figures)
    • C: 17.56 kg m s−117.56\,\text{kg m s}^{-1}17.56kg m s−1 ❌
    • D: 17.57 kg m s−117.57\,\text{kg m s}^{-1}17.57kg m s−1 ❌
  6. Final answer

    The correct recorded magnitude of momentum is 17.6 kg m s−1\boxed{17.6\,\text{kg m s}^{-1}}17.6kg m s−1​

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