JEE MainPhysicsRotational MotionMCQ+4 / −1
Three solid spheres each of mass m and diameter d are stuck together such that the lines connecting the centres form an equilateral triangle of side of length d. The ratio I0/IA of moment of inertia I0 of the system about an axis passing the centroid and about center of any of the spheres IA and perpendicular to the plane of the triangle is :- A
- B
- C
- D
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Correct answer: A
- Given data
- Three identical solid spheres
- Mass of each sphere
- Diameter of each sphere so radius of each sphere is
- Their centres form an equilateral triangle of side .
We need the ratio where:
- = moment of inertia of the system about an axis through the centroid of the triangle and perpendicular to its plane.
- = moment of inertia of the system about an axis through the centre of any one sphere and perpendicular to the plane.
- Moment of inertia of one solid sphere about its own centre
For a solid sphere,
- Distance of each sphere centre from centroid of the equilateral triangle
For an equilateral triangle of side , distance from centroid to each vertex is
So for each sphere, using parallel axis theorem about the centroidal axis,
For three spheres,
- Moment of inertia about axis through centre of one sphere
Let the axis pass through the centre of sphere and be perpendicular to the plane.
-
For sphere itself:
-
The other two sphere centres are each at distance from this axis, since side of triangle is .
For each of those spheres,
Thus total
- Required ratio
- Option check
- A: ✅
- B: ❌
- C: ❌
- D: ❌
So the correct option is A.
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