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Motion in A Plane question

2023 · 6 Apr · Shift 1 · Q46
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  5. /2023 · 6 Apr · Shift 1 · Q46

Motion in A Plane question

2023 · 6 Apr · Shift 1 · Q46

JEE MainPhysicsMotion in A PlaneMCQ+4 / −1
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R Assertion A : When a body is projected at an angle 45∘45^{\circ}45∘, it's range is maximum. Reason R : For maximum range, the value of sin⁡2θ\sin 2 \thetasin2θ should be equal to one. In the light of the above statements, choose the correct answer from the options given below:
  1. A
    Both A\mathbf{A}A and R\mathbf{R}R are correct and R\mathbf{R}R is the correct explanation of A\mathbf{A}A
  2. B
    A\mathbf{A}A is true but R\mathbf{R}R is false
  3. C
    A\mathbf{A}A is false but R\mathbf{R}R is true
  4. D
    Both A\mathbf{A}A and R\mathbf{R}R are correct but R\mathbf{R}R is NOT the correct explanation of A\mathbf{A}A
View written solutionFree

Correct answer: A

  1. Write the formula for horizontal range

For a projectile projected with speed uuu at an angle θ\thetaθ with the horizontal, the horizontal range is

R=u2sin⁡2θgR = \frac{u^2 \sin 2\theta}{g}R=gu2sin2θ​

where ggg is acceleration due to gravity.

  1. Check Assertion A

Assertion A says: When a body is projected at an angle 45∘45^\circ45∘, its range is maximum.

From the formula,

R∝sin⁡2θR \propto \sin 2\thetaR∝sin2θ

The maximum value of sin⁡2θ\sin 2\thetasin2θ is 111.

So maximum range occurs when

sin⁡2θ=1\sin 2\theta = 1sin2θ=1

which gives

2θ=90∘⇒θ=45∘2\theta = 90^\circ \Rightarrow \theta = 45^\circ2θ=90∘⇒θ=45∘

Hence, Assertion A is true.

  1. Check Reason R

Reason R says: For maximum range, the value of sin⁡2θ\sin 2\thetasin2θ should be equal to one.

This is directly true, because from

R=u2sin⁡2θgR = \frac{u^2 \sin 2\theta}{g}R=gu2sin2θ​

range is maximum when sin⁡2θ\sin 2\thetasin2θ is maximum, and its maximum value is 111.

Hence, Reason R is true.

  1. Check whether R explains A

Reason R correctly explains why the range is maximum at 45∘45^\circ45∘:

sin⁡2θ=1⇒2θ=90∘⇒θ=45∘\sin 2\theta = 1 \Rightarrow 2\theta = 90^\circ \Rightarrow \theta = 45^\circsin2θ=1⇒2θ=90∘⇒θ=45∘

So R is the correct explanation of A.

  1. Conclusion

Both Assertion A and Reason R are correct, and Reason R correctly explains Assertion A.

Therefore, the correct option is:

A\boxed{\text{A}}A​

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