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Gravitation question

2020 · 4 Sep · Shift 1 · Q45
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Gravitation question

2020 · 4 Sep · Shift 1 · Q45

JEE MainPhysicsGravitationMCQ+4 / −1
On the x-axis and at a distance x from the origin, the gravitational field due a mass distribution is given by Ax(x2+a2)3/2{{Ax} \over {{{\left( {{x^2} + {a^2}} \right)}^{3/2}}}}(x2+a2)3/2Ax​ in the x-direction. The magnitude of gravitational potential on the x-axis at a distance x, taking its value to be zero at infinity, is:
  1. A
    A(x2+a2)3/2{A{{\left( {{x^2} + {a^2}} \right)}^{3/2}}}A(x2+a2)3/2
  2. B
    A(x2+a2)1/2{A{{\left( {{x^2} + {a^2}} \right)}^{1/2}}}A(x2+a2)1/2
  3. C
    A(x2+a2)1/2{A \over {{{\left( {{x^2} + {a^2}} \right)}^{1/2}}}}(x2+a2)1/2A​
  4. D
    A(x2+a2)3/2{A \over {{{\left( {{x^2} + {a^2}} \right)}^{3/2}}}}(x2+a2)3/2A​
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