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Electrostatics question

2025 · 7 Apr · Shift 2 · Q72

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2025 · 7 Apr · Shift 2 · Q72

Electrostatics question

2025 · 7 Apr · Shift 2 · Q72

JEE MainPhysicsElectrostaticsNumerical+4 / −1

The electric field in a region is given by

\overrightarrow{\mathrm{E}}=(2 \hat{i}+4 \hat{j}+6 \hat{k}) \times 10^3 \mathrm{~N} / \mathrm{C}

. The flux of the field through a rectangular surface parallel to

x-z

plane is

6.0 \,\mathrm{Nm}^2 \mathrm{C}^{-1}

. The area of the surface is

\underline{\hspace{2cm}}\mathrm{cm}^2

.

Numerical answer

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