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Electrostatics question

2020 · 4 Sep · Shift 1 · Q49
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Electrostatics question

2020 · 4 Sep · Shift 1 · Q49

JEE MainPhysicsElectrostaticsMCQ+4 / −1
A two point charges 4q and -q are fixed on the x-axis at x = −d2- {d \over 2}−2d​ and x =d2{d \over 2}2d​ respectively. If a third point charge 'q' is taken from the origin to x = d along the semicircle as shown in the figure, the energy of the charge will : JEE Main 2020 (Online) 4th September Morning Slot Physics - Electrostatics Question 174 English
  1. A
    increase by 3q24πε0d{{3{q^2}} \over {4\pi {\varepsilon _0}d}}4πε0​d3q2​
  2. B
    increase by 2q23πε0d{{2{q^2}} \over {3\pi {\varepsilon _0}d}}3πε0​d2q2​
  3. C
    decrease by q24πε0d{{{q^2}} \over {4\pi {\varepsilon _0}d}}4πε0​dq2​
  4. D
    decrease by 4q23πε0d{{4{q^2}} \over {3\pi {\varepsilon _0}d}}3πε0​d4q2​
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