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Electrostatics question

2017 · 9 Apr · Shift 1 · Q72

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JEE Main
Physics
Electrostatics
2017 · 9 Apr · Shift 1 · Q72

Electrostatics question

2017 · 9 Apr · Shift 1 · Q72

JEE MainPhysicsElectrostaticsMCQ+4 / −1

Four closed surfaces and corresponding charge distributions are shown below. JEE Main 2017 (Online) 9th April Morning Slot Physics - Electrostatics Question 210 English

JEE Main 2017 (Online) 9th April Morning Slot Physics - Electrostatics Question 210 English

Let the respective electric fluxes through the surfaces be

{\Phi _1},{\Phi _2},{\Phi _3}

and

{\Phi _4}

. Then :

A
${\Phi _1}$ < ${\Phi _2}$ = ${\Phi _3}$ > ${\Phi _4}$
B
${\Phi _1}$ > ${\Phi _2}$ > ${\Phi _3}$ > ${\Phi _4}$
C
${\Phi _1}$ = ${\Phi _2}$ = ${\Phi _3}$ = ${\Phi _4}$
D
${\Phi _1}$ > ${\Phi _3}$ ; ${\Phi _2}$ < ${\Phi _4}$

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