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Electrostatics question

2006 · Shift 0 · Q116
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Electrostatics question

2006 · Shift 0 · Q116

JEE MainPhysicsElectrostaticsMCQ+4 / −1
Two insulating plates are both uniformly charged in such a way that the potential difference between them is V2−V1=20 V.{V_2} - {V_1} = 20\,V.V2​−V1​=20V.(i.e., plate 222 is at a higher potential). The plates are separated by d=0.1md=0.1md=0.1m and can be treated as infinitely large. An electron is released from rest on the inner surface of plate 1.1.1. What is its speed when it hits plate 222? (e=1.6×10−19 C,  me=9.11×10−31 kg)\left( {e = 1.6 \times {{10}^{ - 19}}\,C,\,\,{m_e} = 9.11 \times {{10}^{ - 31}}\,kg} \right)(e=1.6×10−19C,me​=9.11×10−31kg) AIEEE 2006 Physics - Electrostatics Question 237 English
  1. A
    2.65×106 m/s2.65 \times {10^6}\,m/s2.65×106m/s
  2. B
    7.02×1012 m/s7.02 \times {10^{12}}\,m/s7.02×1012m/s
  3. C
    1.87×106 m/s1.87 \times {10^6}\,m/s1.87×106m/s
  4. D
    32×10−19 m/s32 \times {10^{ - 19}}\,m/s32×10−19m/s
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