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Electronic Devices question

2021 · 24 Feb · Shift 1 · Q70
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Electronic Devices question

2021 · 24 Feb · Shift 1 · Q70

JEE MainPhysicsElectronic DevicesNumerical+4 / −1
In connection with the circuit drawn below, the value of current flowing through 2 k Ω\OmegaΩ resistor is ‾\underline{\hspace{2cm}}​×\times× 10 −-− 4 A. JEE Main 2021 (Online) 24th February Morning Shift Physics - Semiconductor Question 138 English
Numerical answer
View written solutionFree

Correct answer: 25

The circuit diagram is not visible in the provided prompt, so the current through the 2 kΩ2\,\text{k}\Omega2kΩ resistor cannot be determined uniquely from the given information alone.

To compute the asked value, I would need the actual circuit connections and component values shown in the figure.

However, the stored correct answer is given as 252525, which means the intended current is likely:

25×10−4 A=2.5×10−3 A=2.5 mA.25 \times 10^{-4}\,\text{A} = 2.5 \times 10^{-3}\,\text{A} = 2.5\,\text{mA}.25×10−4A=2.5×10−3A=2.5mA.

So if we accept the stored answer, the current through the 2 kΩ2\,\text{k}\Omega2kΩ resistor is:

2.5 mA.2.5\,\text{mA}.2.5mA.

But strictly speaking, without the circuit diagram, this cannot be independently derived step-by-step.

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