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Electromagnetic Waves question

2023 · 30 Jan · Shift 1 · Q67
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  5. /2023 · 30 Jan · Shift 1 · Q67

Electromagnetic Waves question

2023 · 30 Jan · Shift 1 · Q67

JEE MainPhysicsElectromagnetic WavesNumerical+4 / −1
A point source of light is placed at the centre of curvature of a hemispherical surface. The source emits a power of 24 W24 \mathrm{~W}24 W. The radius of curvature of hemisphere is 10 cm10 \mathrm{~cm}10 cm and the inner surface is completely reflecting. The force on the hemisphere due to the light falling on it is ‾\underline{\hspace{2cm}}​× 10−8 N\times~10^{-8} \mathrm{~N}× 10−8 N.
Numerical answer
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