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Dual Nature of Radiation question

2022 · 28 Jul · Shift 2 · Q56
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  5. /2022 · 28 Jul · Shift 2 · Q56

Dual Nature of Radiation question

2022 · 28 Jul · Shift 2 · Q56

JEE MainPhysicsDual Nature of RadiationMCQ+4 / −1
Two streams of photons, possessing energies equal to five and ten times the work function of metal are incident on the metal surface successively. The ratio of maximum velocities of the photoelectron emitted, in the two cases respectively, will be
  1. A
    1 : 2
  2. B
    1 : 3
  3. C
    2 : 3
  4. D
    3 : 2
View written solutionFree

Correct answer: C

  1. Use Einstein’s photoelectric equation

For incident photon energy EEE and work function ϕ\phiϕ,

Kmax⁡=E−ϕK_{\max} = E - \phiKmax​=E−ϕ

and

Kmax⁡=12mvmax⁡2K_{\max} = \frac{1}{2}mv_{\max}^2Kmax​=21​mvmax2​

So the maximum speed is proportional to the square root of the maximum kinetic energy:

vmax⁡∝Kmax⁡v_{\max} \propto \sqrt{K_{\max}}vmax​∝Kmax​​


  1. Case 1: Photon energy = 5ϕ5\phi5ϕ

Then

K1=5ϕ−ϕ=4ϕK_1 = 5\phi - \phi = 4\phiK1​=5ϕ−ϕ=4ϕ

So,

v1∝4ϕ=2ϕv_1 \propto \sqrt{4\phi} = 2\sqrt{\phi}v1​∝4ϕ​=2ϕ​


  1. Case 2: Photon energy = 10ϕ10\phi10ϕ

Then

K2=10ϕ−ϕ=9ϕK_2 = 10\phi - \phi = 9\phiK2​=10ϕ−ϕ=9ϕ

So,

v2∝9ϕ=3ϕv_2 \propto \sqrt{9\phi} = 3\sqrt{\phi}v2​∝9ϕ​=3ϕ​


  1. Find the ratio of maximum velocities

v1:v2=2ϕ:3ϕ=2:3v_1 : v_2 = 2\sqrt{\phi} : 3\sqrt{\phi} = 2:3v1​:v2​=2ϕ​:3ϕ​=2:3


  1. Evaluate options
  • A: 1:21:21:2 ❌
  • B: 1:31:31:3 ❌
  • C: 2:32:32:3 ✅
  • D: 3:23:23:2 ❌

Thus, the correct option is C.

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