JEE MainPhysicsDual Nature of RadiationMCQ+4 / −1
The light of two different frequencies whose photons have energies 3.8 eV and 1.4 eV respectively, illuminate a metallic surface whose work function is 0.6 eV successively. The ratio of maximum speeds of emitted electrons for the two frequencies respectively will be :
- A1 : 1
- B2 : 1
- C4 : 1
- D1 : 4
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Correct answer: B
- Use Einstein’s photoelectric equation
For photoelectric emission, where:
- = maximum kinetic energy of emitted electron
- = photon energy
- = work function
Given work function:
Photon energies are:
- First light:
- Second light:
- Find maximum kinetic energies
For the first frequency:
For the second frequency:
- Relate kinetic energy to speed
Since for electrons of the same mass,
Therefore,
So the ratio of maximum speeds is:
- Check options
- A: ❌
- B: ✅
- C: ❌
- D: ❌
Hence, the correct option is B.
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