JEE MainPhysicsCurrent ElectricityMCQ+4 / −1
A cell of emf 90 V is connected across series combination of two resistors each of 100 resistance. A voltmeter of resistance 400 is used to measure the potential difference across each resistor. The reading of the voltmeter will be :
- A40 V
- B90 V
- C45 V
- D80 V
View written solutionFree
Correct answer: A
- Given data
- Cell emf:
- Two resistors in series:
- Voltmeter resistance:
We need the reading of the voltmeter when it is connected across each resistor.
- Important idea
A voltmeter has finite resistance, so when connected across a resistor, it is in parallel with that resistor.
So, if the voltmeter is connected across one resistor, the effective resistance of that branch becomes:
Thus the circuit becomes:
- one branch of (resistor in parallel with voltmeter), in series with
- the other resistor.
So total resistance is:
- Find total current
Using Ohm's law,
- Find voltage across the branch containing voltmeter
The voltmeter reads the voltage across the parallel branch, whose equivalent resistance is .
So,
Hence the voltmeter reading is:
- Check options
- A: ✅
- B: ❌
- C: ❌
- D: ❌
So the correct option is A.
- Comparison with stored answer
Stored correct answer: A
Our derived answer: A
They match.
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