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Current Electricity question

2023 · 24 Jan · Shift 2 · Q48
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  5. /2023 · 24 Jan · Shift 2 · Q48

Current Electricity question

2023 · 24 Jan · Shift 2 · Q48

JEE MainPhysicsCurrent ElectricityMCQ+4 / −1
A cell of emf 90 V is connected across series combination of two resistors each of 100 Ω\OmegaΩ resistance. A voltmeter of resistance 400 Ω\OmegaΩ is used to measure the potential difference across each resistor. The reading of the voltmeter will be :
  1. A
    40 V
  2. B
    90 V
  3. C
    45 V
  4. D
    80 V
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