1. Goal of the experiment

To verify Ohm’s law for the test resistor $R_T=10\,\Omega$, we need a circuit with:

• an ammeter in series with $R_T$
• a voltmeter in parallel across $R_T$
• a variable voltage source to vary current/voltage.

So the main task is to see how the given galvanometers can be converted into a suitable ammeter and voltmeter.

2. How to convert a galvanometer

A galvanometer can be converted into:

• Ammeter: by connecting a very small resistance in parallel (shunt)
• Voltmeter: by connecting a very large resistance in series (multiplier)

Given:

• $R_1=10\,\text{M}\Omega$ (very large)
• $R_2=0.001\,\Omega$ (very small)

Therefore:

• use $R_2$ with one galvanometer to make an ammeter
• use $R_1$ with the other galvanometer to make a voltmeter

3. Placement in the Ohm’s law circuit

For correct verification of Ohm’s law:

• the ammeter should be in series with $R_T$
• the voltmeter should be connected across $R_T$

Thus the correct circuit must show:

• one galvanometer with $R_2$ as a shunt, placed in series
• the other galvanometer with $R_1$ in series, connected in parallel across $R_T$

4. Identifying the correct option

Among the options, the one that satisfies both conditions above is Option C.

5. Final answer

The most suitable circuit is:

$\boxed{\text{C}}$

6. Comparison with stored answer

Stored correct answer: C

My derived answer: C

Hence, they agree.