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Alternating Current question

2021 · 17 Mar · Shift 1 · Q55
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  5. /2021 · 17 Mar · Shift 1 · Q55

Alternating Current question

2021 · 17 Mar · Shift 1 · Q55

JEE MainPhysicsAlternating CurrentMCQ+4 / −1
An AC current is given by I = I1 sin ω\omegaω t + I2 cos ω\omegaω t. A hot wire ammeter will give a reading :
  1. A
    I1+I22{{{I_1} + {I_2}} \over {\sqrt 2 }}2​I1​+I2​​
  2. B
    I12−I222\sqrt {{{I_1^2 - I_2^2} \over 2}}2I12​−I22​​​
  3. C
    I12+I222\sqrt {{{I_1^2 + I_2^2} \over 2}}2I12​+I22​​​
  4. D
    I1+I222{{{I_1} + {I_2}} \over {2\sqrt 2 }}22​I1​+I2​​
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