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Limits Continuity and Differentiability · 2023 · 29 Jan · Shift 1

1 Mathematics questions from this JEE Main paper

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JEE Main
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2023 · 29 Jan · Shift 1
Mathematics
Limits Continuity and Differentiability

Limits Continuity and Differentiability · 2023 · 29 Jan · Shift 1

1 Mathematics questions from this JEE Main paper

Q40.Let $x = 2$ be a root of the equation $x^{2} + p x + q = 0$ and $f (x) = {\frac{1 - c o s ( x ^{2} - 4 p x + q ^{2} + 8 q + 16 )}{( x - 2 p ) ^{4}}, 0, x e 2 p x = 2 p$ Then $x \to 2 p^{+} lim [f (x)]$ …
Mathematics · Limits Continuity and Differentiability · MCQ