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3D Geometry · 2023 · 10 Apr · Shift 1

1 Mathematics questions from this JEE Main paper

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JEE Main
Papers
2023 · 10 Apr · Shift 1
Mathematics
3D Geometry

3D Geometry · 2023 · 10 Apr · Shift 1

1 Mathematics questions from this JEE Main paper

Q25.The shortest distance between the lines $\frac{x + 2}{1} = \frac{y}{- 2} = \frac{z - 5}{2}$ and $\frac{x - 4}{1} = \frac{y - 1}{2} = \frac{z + 3}{0}$ is :
Mathematics · 3D Geometry · MCQ