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Vector Algebra question

2023 · 8 Apr · Shift 1 · Q43
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  5. /2023 · 8 Apr · Shift 1 · Q43

Vector Algebra question

2023 · 8 Apr · Shift 1 · Q43

JEE MainMathematicsVector AlgebraNumerical+4 / −1
Let a⃗=6i^+9j^+12k^,b⃗=αi^+11j^−2k^\vec{a}=6 \hat{i}+9 \hat{j}+12 \hat{k}, \vec{b}=\alpha \hat{i}+11 \hat{j}-2 \hat{k}a=6i^+9j^​+12k^,b=αi^+11j^​−2k^ and c⃗\vec{c}c be vectors such that a⃗×c⃗=a⃗×b⃗\vec{a} \times \vec{c}=\vec{a} \times \vec{b}a×c=a×b. If a⃗⋅c⃗=−12,c⃗⋅(i^−2j^+k^)=5\vec{a} \cdot \vec{c}=-12, \vec{c} \cdot(\hat{i}-2 \hat{j}+\hat{k})=5a⋅c=−12,c⋅(i^−2j^​+k^)=5, then c⃗⋅(i^+j^+k^)\vec{c} \cdot(\hat{i}+\hat{j}+\hat{k})c⋅(i^+j^​+k^) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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