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Sets and Relations question

2012 · Shift 0 · Q23
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  5. /2012 · Shift 0 · Q23

Sets and Relations question

2012 · Shift 0 · Q23

JEE MainMathematicsSets and RelationsMCQ+4 / −1
Let X = {1, 2, 3, 4, 5}. The number of different ordered pairs (Y, Z) that can be formed such that Y ⊆\subseteq⊆ X, Z ⊆\subseteq⊆ X and Y ∩\cap∩ Z is empty, is :
  1. A
    35
  2. B
    25
  3. C
    53
  4. D
    52
View written solutionFree

Correct answer: 243

  1. We need the number of ordered pairs (Y,Z)(Y,Z)(Y,Z) such that

    • Y⊆XY \subseteq XY⊆X
    • Z⊆XZ \subseteq XZ⊆X
    • Y∩Z=∅Y \cap Z = \varnothingY∩Z=∅

    where X={1,2,3,4,5}X=\{1,2,3,4,5\}X={1,2,3,4,5}.

  2. Since YYY and ZZZ are disjoint, each element of XXX has exactly 3 choices:

    • it belongs to YYY
    • it belongs to ZZZ
    • it belongs to neither YYY nor ZZZ

    It cannot belong to both because Y∩Z=∅Y \cap Z = \varnothingY∩Z=∅.

  3. Since XXX has 555 elements, total number of ordered pairs (Y,Z)(Y,Z)(Y,Z) is 35=243.3^5 = 243.35=243.

  4. Because the pair is ordered, (Y,Z)(Y,Z)(Y,Z) and (Z,Y)(Z,Y)(Z,Y) are counted separately when Y≠ZY \neq ZY=Z.

  5. Therefore, the required number is 243.243.243.

  6. Now compare with the given options:

    • A: 353535
    • B: 252525
    • C: 535353
    • D: 525252

    None of these matches 243243243.

So the mathematically correct answer is 243243243, which is not among the listed options. Hence the stored answer appears to be incorrect.

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