JEE MainMathematicsPermutations and CombinationsNumerical+4 / −1
Let b1b2b3b4 be a 4-element permutation with bi {1, 2, 3, ........, 100} for 1 i 4 and bi bj for i j, such that either b1, b2, b3 are consecutive integers or b2, b3, b4 are consecutive integers. Then the number of such permutations b1b2b3b4 is equal to .
Numerical answer
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