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Parabola question

2005 · Shift 0 · Q108
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Parabola question

2005 · Shift 0 · Q108

JEE MainMathematicsParabolaMCQ+4 / −1
Let PPP be the point (1,0)(1, 0)(1,0) and QQQ a point on the parabola y2=8x{y^2} = 8xy2=8x. The locus of mid point of PQPQPQ is :
  1. A
    y2−4x+2=0{y^2} - 4x + 2 = 0y2−4x+2=0
  2. B
    y2+4x+2=0{y^2} + 4x + 2 = 0y2+4x+2=0
  3. C
    x2+4y+2=0{x^2} + 4y + 2 = 0x2+4y+2=0
  4. D
    x2−4y+2=0{x^2} - 4y + 2 = 0x2−4y+2=0
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