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Matrices and Determinants question

2022 · 28 Jul · Shift 1 · Q42
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Matrices and Determinants question

2022 · 28 Jul · Shift 1 · Q42

JEE MainMathematicsMatrices and DeterminantsNumerical+4 / −1
Let A=[1−12α]A=\left[\begin{array}{cc}1 & -1 \\ 2 & \alpha\end{array}\right]A=[12​−1α​] and B=[β110],α,β∈RB=\left[\begin{array}{cc}\beta & 1 \\ 1 & 0\end{array}\right], \alpha, \beta \in \mathbf{R}B=[β1​10​],α,β∈R. Let α1\alpha_{1}α1​ be the value of α\alphaα which satisfies (A+B)2=A2+[2222](\mathrm{A}+\mathrm{B})^{2}=\mathrm{A}^{2}+\left[\begin{array}{ll}2 & 2 \\ 2 & 2\end{array}\right](A+B)2=A2+[22​22​] and α2\alpha_{2}α2​ be the value of α\alphaα which satisfies (A+B)2=B2(\mathrm{A}+\mathrm{B})^{2}=\mathrm{B}^{2}(A+B)2=B2. Then ∣α1−α2∣\left|\alpha_{1}-\alpha_{2}\right|∣α1​−α2​∣ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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