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Matrices and Determinants question

2021 · 25 Feb · Shift 1 · Q40
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Matrices and Determinants question

2021 · 25 Feb · Shift 1 · Q40

JEE MainMathematicsMatrices and DeterminantsNumerical+4 / −1
If A=[0−tan⁡(θ2)tan⁡(θ2)0]A = \left[ {\begin{matrix} 0 & { - \tan \left( {{\theta \over 2}} \right)} \\ {\tan \left( {{\theta \over 2}} \right)} & 0 \\ \end{matrix} } \right]A=[0tan(2θ​)​−tan(2θ​)0​] and (I2+A)(I2−A)−1=[a−bba]({I_2} + A){({I_2} - A)^{ - 1}} = \left[ {\begin{matrix} a & { - b} \\ b & a \\ \end{matrix} } \right](I2​+A)(I2​−A)−1=[ab​−ba​], then 13(a2+b2)13({a^2} + {b^2})13(a2+b2) is equal to
Numerical answer
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