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Matrices and Determinants question

2021 · 18 Mar · Shift 1 · Q26
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  5. /2021 · 18 Mar · Shift 1 · Q26

Matrices and Determinants question

2021 · 18 Mar · Shift 1 · Q26

JEE MainMathematicsMatrices and DeterminantsMCQ+4 / −1
The solutions of the equation ∣1+sin⁡2xsin⁡2xsin⁡2xcos⁡2x1+cos⁡2xcos⁡2x4sin⁡2x4sin⁡2x1+4sin⁡2x∣=0,(0<x<π)\left| {\begin{matrix} {1 + {{\sin }^2}x} & {{{\sin }^2}x} & {{{\sin }^2}x} \\ {{{\cos }^2}x} & {1 + {{\cos }^2}x} & {{{\cos }^2}x} \\ {4\sin 2x} & {4\sin 2x} & {1 + 4\sin 2x} \\ \end{matrix} } \right| = 0,(0 \lt x \lt \pi )​1+sin2xcos2x4sin2x​sin2x1+cos2x4sin2x​sin2xcos2x1+4sin2x​​=0,(0<x<π), are
  1. A
    π12,π6{\pi \over {12}},{\pi \over 6}12π​,6π​
  2. B
    π6,5π6{\pi \over 6},{{5\pi } \over 6}6π​,65π​
  3. C
    5π12,7π12{{5\pi } \over {12}},{{7\pi } \over {12}}125π​,127π​
  4. D
    7π12,11π12{{7\pi } \over {12}},{{11\pi } \over {12}}127π​,1211π​
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