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Inverse Trigonometric Functions question

2022 · 29 Jun · Shift 1 · Q38
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  5. /2022 · 29 Jun · Shift 1 · Q38

Inverse Trigonometric Functions question

2022 · 29 Jun · Shift 1 · Q38

JEE MainMathematicsInverse Trigonometric FunctionsNumerical+4 / −1
50tan⁡(3tan⁡−1(12)+2cos⁡−1(15))+42tan⁡(12tan⁡−1(22))50\tan \left( {3{{\tan }^{ - 1}}\left( {{1 \over 2}} \right) + 2{{\cos }^{ - 1}}\left( {{1 \over {\sqrt 5 }}} \right)} \right) + 4\sqrt 2 \tan \left( {{1 \over 2}{{\tan }^{ - 1}}(2\sqrt 2 )} \right)50tan(3tan−1(21​)+2cos−1(5​1​))+42​tan(21​tan−1(22​)) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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